2r^2+1r+13=4

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Solution for 2r^2+1r+13=4 equation:


Simplifying
2r2 + 1r + 13 = 4

Reorder the terms:
13 + 1r + 2r2 = 4

Solving
13 + 1r + 2r2 = 4

Solving for variable 'r'.

Reorder the terms:
13 + -4 + 1r + 2r2 = 4 + -4

Combine like terms: 13 + -4 = 9
9 + 1r + 2r2 = 4 + -4

Combine like terms: 4 + -4 = 0
9 + 1r + 2r2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
4.5 + 0.5r + r2 = 0

Move the constant term to the right:

Add '-4.5' to each side of the equation.
4.5 + 0.5r + -4.5 + r2 = 0 + -4.5

Reorder the terms:
4.5 + -4.5 + 0.5r + r2 = 0 + -4.5

Combine like terms: 4.5 + -4.5 = 0.0
0.0 + 0.5r + r2 = 0 + -4.5
0.5r + r2 = 0 + -4.5

Combine like terms: 0 + -4.5 = -4.5
0.5r + r2 = -4.5

The r term is 0.5r.  Take half its coefficient (0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
0.5r + 0.0625 + r2 = -4.5 + 0.0625

Reorder the terms:
0.0625 + 0.5r + r2 = -4.5 + 0.0625

Combine like terms: -4.5 + 0.0625 = -4.4375
0.0625 + 0.5r + r2 = -4.4375

Factor a perfect square on the left side:
(r + 0.25)(r + 0.25) = -4.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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